================================================================================ - Sample space: the set which contains all possible events. - Example: * Trial: toss a coin one time. * Sample space $$$S=\{H,T\}$$$ * H, T from S: sample points * Possible events (subset of S): $$$\phi$$$ (event where you get nothing), {H} (event where you get H), {T} (event where you get T), {H,T} (event you get H or T) * {H}, {T} from all possible events: fundamental events which composed of sample points * {H,T}: event, fundamental events $$$\in$$$ event * Probability: function, domain is all possible events, range is numbers $$$\text{domain: all possible events} \xrightarrow {\text{Probability as function}} \text{numbers as probability value}$$$
numbers_as_probability_value=probability_as_function(all_possible_events)
This is notes which I wrote as I take following lecture http://www.kocw.net/home/search/kemView.do?kemId=1189957 - Probability_space_Axioms_on_probability ================================================================================ If sample space S is mapped to probability values, sample space S is mapped to probability space. Each event has probability value in probability space. ================================================================================ Axioms on probability - $$$0 \le P[A_i]$$$ $$$A_i$$$: ith event $$$P[A_i]$$$: probability value of ith event A occuring - $$$\sum\limits_{i=1}^n P[A_i]=1$$$ - If $$$A_i \cap A_j = \phi$$$, then, $$$P[A_i \cup A_j] = P[A_i] + P[A_j]$$$ For example, $$$P(\{H \cup T\})=P(\{H\})+P(\{T\})$$$ ================================================================================ Expanded characteristics of probability from axioms - $$$P[A^c]=1-P[A]$$$ - $$$P[A] \le 1$$$ - $$$P[\phi] = 0$$$ - When $$$\{A_1,A_2,\cdots,A_N\}$$$ is given, if $$${A_i\cap A_j=\phi}$$$ is true, then, $$$P[\cup_{k=1}^N A_k]=\sum\limits_{k=1}^N P[A_k]$$$ - $$$P[A_1\cup A_2]=P[A_1]+P[A_2]-P[A_1\cap A_2]$$$ - $$$P[\cup_{k=1}^N A_k]=\sum\limits_{k=1}^N P[A_k] - \sum\limits_{j\lt k}^N P[A_k\cap A_j]+\cdots+(-1)^{N+1} P[A_1\cap A_2 \cap \cdots \cap A_N]$$$ - If $$$A_1 \subset A_2$$$ is true, then, $$$P[A_1] \le P[A_2]$$$