001-4. Operator - if statement
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# Day_01_03_if.py
# I want to know value of a is either odd or even
a = 13
# If you devide some value by 2, remainder is either some value or 0
# In terms of programming, when you devide value by 2, and it doesn't create remainder, it is even
print(a%2)
# In Python, after colon, you need indent in next line which writes detailed contents
if a%2 == 1:
print('홀수')
else:
print('짝수')
# If a=13, a%2 = 1, 1 is true
if a%2:
print('홀수')
else:
print('짝수')
# If a=13, 13 is true
if a:
print('홀수')
else:
print('짝수')
if a:
print('홀수')
# Quiz
# You get one number between 0 to 999
# and guess how many digits do that number have
a = input('number : ')
print(type(a))
# output: string
a = int(input('number : '))
# Suppose a = 128
a = 128
print(type(a))
# if statement chooses one out of two
# But this quiz is quiz to choose one out of three
# Method1
if a >= 100:
print(3)
if 100 > a >= 10:
print(2)
if 10 > a >= 0:
print(1)
# Method2
if a >= 100:
print(3)
else:
# print(2, 1)
if a >= 10:
print(2)
else:
print(1)
# Method3
a1, a2, a3 = bool(a//100), bool(a//10), bool(a//1)
print(a1 + a2 + a3)
# Method4
digit = 1
# if a >= 100: digit = digit+1; a = a // 10
# if a >= 10: digit = digit+1; a = a // 10
if a >= 10: digit = digit+1; a = a // 10
if a >= 10: digit = digit+1; a = a // 10
print(digit)
if a >= 100:
print(3)
elif a >= 10:
print(2)
else:
print(1)
if a >= 100:
print(3)
else:
# print(2, 1)
if a >= 10:
print(2)
else:
print(1)
print('end')
# whitespace(space, newline, tab) is ignored by Python interpreter
# print( 'hi')
# print(
# 'hi'
# )
# print(
# 'hi')
# Python one line syntax
if a >= 100:
print(3)
else:
if a >= 10:
print(2)
else:
print(1)
# Whitespace is ignored by Python interpreter
if a >= 100:
print(3)
else:
if a >= 10:
print(2)
else:
print(1)
# We can elevate if line
if a >= 100:
print(3)
else:if a >= 10:
print(2)
else:
print(1)
# We can remove duplicated colon, then, we get "else if" syntax
if a >= 100:
print(3)
else if a >= 10:
print(2)
else:
print(1)
# Python provides elif syntax
if a >= 100:
print(3)
elif a >= 10:
print(2)
else:
print(1)
# If you should choose one out of 9 options,
# you need 9 if
# Skilled ones make algorithms to remove if statement
# 문제
# 2개의 정수 중에서 큰 숫자를 찾는 함수를 만드세요.
# return 키워드 여러 번 사용 가능.
def max2(a, b):
# if a >= b:
# return a
# else:
# return b
# if a >= b:
# return a
# return b
if a >= b:
b = a
return b
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